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Find Whether the point (2,6) lies on, inside or outside the parabola 2x - y2 + 2y +3 = 0.

Pratik Sharma , 15 Years ago
Grade 12
anser 1 Answers
Badiuddin askIITians.ismu Expert

Last Activity: 15 Years ago

Dear pratik

2x - y2 + 2y +3 = 0

convert it in to standard form

(y-1)2 -2(x+2)=0

let S =(y-1)2 -2(x+2)

now put point S1 =17>0

 so point lie outside the parabola

now solve it with another method

 let S =2x - y2 + 2y +3

put point

S1= -17

 this result gives that point lie inside the parabola

 

but you should careful that in standard form coefficient of y2   

 is positive so you must take  y2 as a positive coefficient in general form

so you will take S =-2x + y2 - 2y -3

 

Regards

Badiuddin


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